I was trying to do this in Python 3:
t = {'1': 1, '2':2}
#Trying to sort the dictionary t by its value
sorted(t.items(),
key=lambda (k,v): v, # the left bracket raises syntax error, it works in python 2 but not 3
)
It turns out that in Python 3, tuple parameter unpacking is not supported anymore.
So if more than one parameter is passed into a lambda function, we have to access it like a list:
lambda parameters: parameters[0], parameters[1], parameters[2]
So for the issues I have, the correct code would be:
sorted(t.items(),
key=lambda k_v: k_v[1],
)